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Kinematics in Two Dimension - Kinematika dalam Dua Dimensi -

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Presentasi berjudul: "Kinematics in Two Dimension - Kinematika dalam Dua Dimensi -"— Transcript presentasi:

1 Kinematics in Two Dimension - Kinematika dalam Dua Dimensi -

2 Projectile Motion Gerak Peluru

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5 A projectile motion is a parabolic through which the velocity of any object has its vertical and horizontal components Horizontal component V x0 = V 0 cos  V x = V x0 Constant Velocity x = x 0 + V x0 t

6 Projectile Motion Gerak Peluru A projectile motion is a parabolic through which the velocity of any object has both vertical and horizontal components Vertical component V y0 = V 0 sin  V y = V y0 - gt Constant Acceleration y = y 0 + V y0 t – ½ gt 2 + V y 2 = V y0 2 – 2g ( y – y 0 ) +

7 Projectile Motion Gerak Peluru A movie stunt driver on a motor cycle speeds horizontally of a 50-m-high cliff. How fast must the motorcycle leave the cliff off to land on level ground below 90.0 m from the base of the cliff where the cameras are? Ignore the air resistance Seorang stunt man mengendarai motor saat untuk pengambilan gambar film dari tebing setinggi 50 m dari tanah. Berapakah kecepatan motor agar bisa mendarat pada jarak 90 meter dari titik tinggal landas tebing? Hambatan udara ditiadakan.

8 Projectile Motion Gerak Peluru

9 A football is kicked at an angle of 37 o with a velocity of 20 m/s. Calculate a) Maximum height, b) the time of travel before the football hits the ground, c) how far away it hits the ground, d) the velocity vector at the maximum height and e) the acceleration vector at the maximum height. Assume the ball leaves the foot at ground level, and ignore air resistance and rotation of the ball. Sebuah bola ditendang mengarah sudut 37 o dengan kecepatan 20 m/s. Hitung a) tinggi maximum bola di udara, b) waktu total saat bola berada di udara dan sesaat sebelum mendarat, c) jarak bola mendarat dari titik tendang, d) Vektor kecepatan saat bola berada di titik tertinggi, dan e) vektor percepatan saat bola berada di titik tertinggi.

10 Projectile Motion Gerak Peluru Horizontal Range ( R ) R = 2 V o 2 g sin θ o cos θ o Vo2Vo2 g sin 2θ o R =

11 Projectile Motion Gerak Peluru Horizontal Range ( R )

12 Uniform Circular Motion Gerak Melingkar Beraturan ω ω = angular speed V = absolute velocity

13 Uniform Circular Motion Gerak Melingkar Beraturan Average angular speed (ω) The rate at which its angular coordinate, the angular displacement θ, changes with time ω av = θ f - θ i t rad / s ω = 2πf ω = Angular speed = Angular frequency

14 Uniform Circular Motion Gerak Melingkar Beraturan Angular acceleration (α) The rate at which its angular speed changes with time α = ω f - ω i t rad / s 2

15 Uniform Circular Motion Gerak Melingkar Beraturan


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