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Hukum Ampere Ampere’s Law Medan magnetik dari kawat lurus panjang I B r ds gunakan Hk Biot-Savart Ambil vektor pendek, ds Perkalian skalar antara B.

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Presentasi berjudul: "Hukum Ampere Ampere’s Law Medan magnetik dari kawat lurus panjang I B r ds gunakan Hk Biot-Savart Ambil vektor pendek, ds Perkalian skalar antara B."— Transcript presentasi:

1

2 Hukum Ampere

3 Ampere’s Law

4 Medan magnetik dari kawat lurus panjang I B r ds gunakan Hk Biot-Savart Ambil vektor pendek, ds Perkalian skalar antara B & vektor pendek ds adalah:

5 Jumlah B.ds di sekitar lintasan lingkaran I B r ds Jumlahkan ini untuk seluruh cincin Keliling lingkaran

6 Jumlah B.ds di sekitar lintasan lingkaran N.B. this does not depend on r In fact it does not depend on path Ampere’s Law:on any closed loop where I is the current flowing through the loop

7 Hukum Ampere B I I B I I Sign comes from direction of loop, current & right hand rule

8 Hukum Ampere B I I Sign comes from direction of loop, current & right hand rule B I I B I I

9 Hukum Ampere No Different Physics from Biot-Savart Law Useful in cases where there is a high degree of symmetry C.f. Coulomb’s Law and Gauss’s Law in electrostatics

10 Quiz 1A 2A Currents of 1A, 5A, 2A, flowing in 3 wires as shown 5A What is  B.ds through loops a, b, c, d? a b c  B.ds-1  0 +3  0 +4  0 +6  0 a b c d

11 Examples of using Ampere’s Law

12 Examples Long-straight wire Insider a long straight wire Toroidal coil Solenoid

13 Long Wire

14 Magnetic Field from a long wire I r By symmetry Ampere’s Law on Loop 2 Loop1 B r1 B || (r 1 ) B r2 B || (r 1 )

15 Magnetic Field from a long wire I r By symmetry For any closed Ampere Loop the radial components will always cancel out B r1 B r4 Loop 2 Loop 3 B r1 B r2 B r3 B r2 Thus there is no way to balance a current by a radial component or produce a radial component from a current

16 Magnetic Field from a long wire I r By symmetry at constant r Tangential component Take a circle of radius r as the Ampere Loop L.H.S. L.H.S. = R.H.S or Q.E.D.

17 Di dalam suatu kawat

18 Di dalam suatu kawat berarus I 0 Asumsikan rapat arus adalah homogen sehingga arus yang mengalir dalam loop adalah A Kita pilih loop Ampere berupa lingkaran dengan jari-jari r r Sama seperti sebelumnnya

19 Medan B dari suatu kawat panjang B r R

20 Toroidal Coil

21 r I0I0 Ampere Loop, circle radius r No current flowing through loop thus B = 0 inside the Toroid Toroid has N loops of wire, carrying a current I 0

22 Toroidal Coil r I0I0 Ampere Loop, circle radius r For each wire going in there is another wire comeing out Thus no nett current flowing through loop thus B = 0 outside the Toroid

23 Toroidal Coil r I0I0 Ampere Loop, circle radius r For each loop of the coil an extra I 0 of current passes through the Ampere Loop Zoom Toroid has N loops of wire

24 Medan B di dalam Toroida Toroid berbentuk donut dengan dililiti koil. Maka, ds r

25 Solenoid

26 Infinitely Long Solenoid Zoom looks very similar to the toroid with a very large radius Wire carrying a current of I 0 wrapped around with n coils per unit length

27 Infinitely Long Solenoid Field at centre is same as torus of infinite radius Wire carrying a current of I 0 wrapped around with n coils per unit length

28 Medan magnet di dalam Solenoida Jika solenoida terdiri dari jumlah lilitan N dan panjang adalah l, maka: ds l

29 Resume Hukum Ampere Lebih mudah dipakai dibandingkan Hukum Biot-Savart dalam banyak kasus Contoh Kawat panjang Dalam kawat Toroida Solenoida


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