# NAMA : RAHMA APRILIA KELAS : 11.2A.05 NIM : 11141704 UKURAN GEJALA PUSAT DATA BELUM DIKELOMPOKKAN STATISTIKA DESKRIPTIF.

## Presentasi berjudul: "NAMA : RAHMA APRILIA KELAS : 11.2A.05 NIM : 11141704 UKURAN GEJALA PUSAT DATA BELUM DIKELOMPOKKAN STATISTIKA DESKRIPTIF."— Transcript presentasi:

NAMA : RAHMA APRILIA KELAS : 11.2A.05 NIM : 11141704 UKURAN GEJALA PUSAT DATA BELUM DIKELOMPOKKAN STATISTIKA DESKRIPTIF

5.Median ( Me ) Dik : X₁ = 3,X₂ = 5, X₃ = 7  Data ganjil, n = 3 maka ; x = ( n – 1 )/ 2 = ( 3 – 1 )/ 2 = 2/2 = 1 Me = Xₓ₊₁ = X₁₊₁ = X₂ = 5  Data genap, n =4, X₁ = 3, X₂ = 5, X₃ = 7, X₄ = 8 maka ; x = n/ 2 = 4/ 2 = 2 Me = ½ (Xₓ + Xₓ₊₁) = ½ (X₂ + X₂₊₁) = ½ ( 5 + 7 ) = ½ ( 12 ) = 6

6. Modus ( Mo ) Dik : X₁ = 3, X₂ = 5, X₃ = 7, X₄ = 7 maka ; Mo = 7  Karena muncul 2x 7. Quartil ( Qᵢ ) Dik : X₁ = 3, X₂ = 5, X₃ = 7, n = 3 maka ; Qᵢ = i ( n + 1 ) / 4 Q₁ = 1 ( 3 + 1 ) / 4  Q₁ = X₁ + 0 ( X₂ – X₁ ) = 1 ( 4) / 4 = 3 + 0 ( 5 – 3 ) = 4/ 4 = 3 + 0 ( 2 ) = 1 = 3 + 0 = 3 Q₂ = 2 ( 3 + 1 ) / 4  Q₂ = X₂ + 0 ( X₃ – X₂ ) = 2 ( 4) / 4 = 5 + 0 ( 7 – 5 ) = 8/ 4 = 5 + 0 ( 2 ) = 2 = 5 + 0 = 5 Q₃ = 3 ( 3 + 1 ) / 4  Q₃ = X₃ + 0 ( X₄ – X₃ ) = 3 ( 4) / 4 = 7 + 0 ( 0 – 7 ) = 12/ 4 = 7 + 0 ( -7 ) = 3 = 7 + 0 = 7 Note : Quartil Ke – 2 = Median

8. Desil ( Dᵢ ) Dik : X₁ = 3,X₂ = 5, X₃ = 7, n = 3 maka ; Dᵢ = i ( n + 1 ) / 10 D₅ = 5 ( 3 + 1 ) /10  D5 = X₂ + 0 ( X₃ – X₂ ) = 5 ( 4 ) / 10 = 5 + 0 ( 7 – 5 ) = 20 /10 = 5 + 0 ( 2 ) = 2 = 5 + 0 = 5 9. Persentil ( Pᵢ ) Dik : X₁ = 3,X₂ = 5, X₃ = 7, n = 3 maka ; Pᵢ = i ( n + 1 ) / 100 P₄₀ = 40 ( 3 + 1 ) /100  P40 = X₁ + 0,6 ( X₂ – X₁ ) = 40 ( 4 ) / 100 = 3 + 0,6 ( 5 – 3 ) = 160 /100 = 3 + 0,6 ( 2 ) = 1,6 = 3 + 1,2 = 4,2

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