Dr. Ir. Yeffry Handoko Putra, M.T

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1 Dr. Ir. Yeffry Handoko Putra, M.T
Sifat-sifat Sistem

2 Kausalitas: Input Output Sistem nonKausal Kausal

3 Fidelity: y(t)=Kx(t-t0)
Input Output Sistem 2r(t) 4r(t-t0) 3r(t) 6r(t-t0) Tanpa distorsi Dengan Amplifikasi 2x K=2 (tidak nol)

4 + Pengukuran Distorsi t-t0 Error(t) - x(t) Sistem yang diuji yi(t)
ya(t) + K Sistem Ideal

5 Linieritas Input Output Sistem Linier 2u(t) 4r(t) 3u(t) 6r(t) + 5u(t)
Superposisi

6 Sistem Linier stasioner
Input Output Sistem Linier stasioner 2u(t) 4r(t) 2u(t-2) 4r(t-2) + Stasioner delay pada input Menyebabkan delay pada output 2u(t)+2u(t-2) 4r(t)+4r(t-2) Superposisi

7 Menyelesaikan Solusi Sistem Linieritas Stasioner
Input Output Sistem Linier Stasioner x(t) =cos(0t) y(t) = 2sin(0t) ? x(t)=2cos(0t)+3cos(20t-1/4) cos(60t-1/2)

8 Menyelesaikan Solusi Sistem Linieritas Stasioner
Input Output Sistem Linier Stasioner x(t) =cos(0t) y(t) = 2sin(0t) x(t)=2cos(0t)+3cos(20t-1/4) cos(60t-1/2) y(t) = 4sin(0t)+6sin(20t-1/4) sin(60t-1/2)

9 Menyelesaikan Solusi Sistem Linieritas Stasioner
Input Output Sistem Linier Stasioner x(t) =cos(0t) y(t) = 2sin(0t-1/4) ? x(t)=2cos(0t)+3cos(20t-1/4) cos(60t-1/2)

10 Menyelesaikan Solusi Sistem Linieritas Stasioner
Input Output Sistem Linier Stasioner x(t) =cos(0t) y(t) = 2sin(0t-1/2) x(t)=2cos(0t)+3cos(20t-1/4) cos(60t-1/2) y(t) = 4sin(0t-1/2 ) sin(20t-1/4- 1/2) sin(60t-1/2-1/2 ) = 4sin(0t- 1/2) sin(20t-3/4) sin(60t-))

11 Tugas 2 Suatu sistem linier stasioner jika diberi input x(t)=u(t) akan menghasilkan output y(t)=3u(t). Tentukan outputnya jika sekarang inputnya adalah deret step: x(t) = 2u(t)-2u(t-2) + 3u(t-4)-3u(t-6) = 2r(t/2) + 3r[(t-4)/2]

12 Energi Sinyal

13 Daya Sinyal

14 Carilah Output 3 (t) 3 y(t) + t-4 x(t)=u(t) =3 (t)+u(t-4) u(t-4)

15 + Carilah Output t-4 3 y(t) x(t)=u(t) =3(t)+u(t-4)
x(t)=2u(t)-2u(t-3)+3u(t-6) y(t)= 6 (t)+6u(t-4) -6 (t-3)-6u(t-7) +9 (t-6)+9u(t-10) ?

16 Carilah Output 3 u (t) 3 y(t) + 4t x(t)=(t) =3 u(t)+ (t) (t)

17 + Carilah Output t-4 4t y(t)=3 u(t)+ (t) x(t)=(t) 3 3 u (t) (t)
v(t)=? t-4 3u(t-4)+ (t-4)

18 + + Tugas 2 carilah output t-2 2t 4t y(t)=? x(t)=2r(t) 3 y(t)=?