Statistika Deskriptif

Presentasi berjudul: "Statistika Deskriptif"— Transcript presentasi:

1 Statistika Deskriptif
Tugas Notasi Sigma

2 Nama : rahma aprilia handayani
KELAS : 11.2A.05 NIM :

3 Notasi Sigma Diketahui : X1 = 3 X2 = 4 X3 = 6 , Y1 = 2 Y2 = 3 Y3 = 1
Variabel X : 2 4. ∑ Xi = (X12 + X22) - 3 = ( )-3 = (9 + 16) – 3 = 25-3 = 22 i=1 5. ∑ (Xi 2 – 3) = (32 - 3) + (42 - 3) = (9-3) + (16-3) = = 19 3 6. ∑ = 3.7 = 21

4 Notasi Sigma Diketahui : X1 = 3 X2 = 4 X3 = 6 , Y1 = 2 Y2 = 3 Y3 = 1
Variabel X : 9. ∑ Xi = (x12 + x22)-4 = ( )-4 = (9 +16)-4 =21 2 i=1 7. ∑ 3Xi 2 = 3Xi2 + 3Xi2 = = = 105 10. ∑ 5Xi2 + 2xi = 5x12 + 2x1 + 5x x2 i=   i= = 8. ∑ (Xi – 3) = (x1 – 3)2 + (x2 – 3)2 = (3- 3)2 + (4-3)2 = i= = = 739

5 Notasi Sigma Diketahui : X1 = 3 X2 = 4 X3 = 6 , Y1 = 2 Y2 = 3 Y3 = 1
Variabel Y : 3 1. ∑ Yi = Y1 + Y2 + Y3 = = 6 i=1 2 2. ∑ 4yi = 4y1 + 4y2 + 4y3 = = = 24 3. ∑ yi = y1 2 + y2 2 = = = 13

6 Notasi Sigma Diketahui : X1 = 3 X2 = 4 X3 = 6 , Y1 = 2 Y2 = 3 Y3 = 1
Variabel Y : 2 4. ∑ yi = (y12 + y22) - 3 = ( )-3 = (4 + 9) – 3 = 13-3 = 10 i=1 5. ∑ (yi 2 – 3) = (y1 2 – 3) + (y2 2 – 3) = (22 - 3) + (32 - 3) = (4-3) + (9-3) = = 7 3 6. ∑ = 3.7 = 21

7 Notasi Sigma Diketahui : X1 = 3 X2 = 4 X3 = 6 , Y1 = 2 Y2 = 3 Y3 = 1
Variabel Y : 2 7. ∑ 3yi 2 = 3y12 + 3y22 = = = 93 i=   8. ∑ (yi – 3) = (y1 – 3)2 + (y2 – 3)2 = (2-3)2 + (3-3)2 = i=1 9. ∑ yi = (y12 + y22)-4 = ( )-4 = (4 + 9)-4 = 9

8 Notasi Sigma Diketahui : X1 = 3 X2 = 4 X3 = 6 , Y1 = 2 Y2 = 3 Y3 = 1
Variabel Y : 2 10. ∑ 5yi2 + 2yi = 5y12 + 2y1 + 5y22 + 2y2 i= = = = 335