Presentasi Statistika Dasar
Agatha Puteri Vitria Wahyuningsih Fisika / 642016009 Hello! Agatha Puteri Vitria Wahyuningsih Fisika / 642016009
1 Menguraikan
Diketahui: μ = mean ( Ho : μ = 20 Ha : μ > 20 t = 3.2 n = 15 PEMBAHASAN SOAL NO 17 Diketahui: μ = mean ( Ho : μ = 20 Ha : μ > 20 t = 3.2 n = 15 Ditanya: Conclusion of the significance levels for a. α = .05 b. α = .01 c. α = .001
2 Jawaban
PEMBAHASAN SOAL NO 17 a. α = .05 t100%-5%;15-1 = qt (0.95,14) t100%-5%;15-1 = 1.76131 b. α = .01 t100%-1%;15-1 = qt (0.99,14) t100%-1%;15-1 = 2.624494 c. α = .001 t100%-0.1;15-1 = qt (0.999,14) t100%-0.1;15-1 = 3.78739 Menggunakan uji hipotesis langsung (one tail) dengan distribusi tabel t
PEMBAHASAN SOAL NO 17
3 Kesimpulan
H0 ditolak Ha diterima b. 3.2 > 2.6... PEMBAHASAN SOAL NO 17 a. 3.2 > 1.7... H0 ditolak Ha diterima b. 3.2 > 2.6... c. 3.2 > 3.7... H0 diterima Ha ditolak
PEMBAHASAN SOAL NO 17 To find the answer, you need to find the probability. The T distribution gives you the probability of something greater occurring, the upper tail area. Since the Ha is >, we can simply use the value we find. The degrees of freedom (df) of a t test is found by taking the number in the sample -1. so 15-1=14. Look up the number 3.2 in the 14 df row, and you get some number between .05 and .01. You dont get a straight answer, but you can see both of these are greater then the significance level of .001, so you cannot reject the null. Therefore your conclusion would be that you cannot say the reflectometer reading average is equal to or greater then 20. Your results show that the data is not statistically significant.
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