Rb Ya A B Xa 5’ 5’ 5’ 5’ D E F 5’ F2= 500 lb G 5’ F1 = 500 lb C
∑X = 0 Xa + Xc = 0 Xa = -Xc Xa = 500 lb ∑Y = 0 -Ya + 500+Rb = 0 ∑Ma = 0 Rb.10-500.5-500.15 = 0 10 Rb.= 2500 + 7500 Rb = 1000 lb Ya = 1500 lb Ya Rb A B Xa 5’ 5’ 5’ 5’ D E F 5’ F2= 500 lb G 5’ F1 = 500 lb C
MENETUKAN GAYA PADA AEGC DALAM KESETIMBNGAN ∑Mg =0 -Xa.10 - Xc.5 + Xe.5 = 0 -500.10 – 500.5 =- 5 Xe Xe = (5000+2500)/5 Xe = 1500 lb ∑Me =0 -Xa.5 - Xc.10 + Xg.5 = 0 -500.5 – 500.10 = -5 Xg Xg = (5000+2500)/5 Xg = 1500 lb Ya Ya Rb A B A Xa Xa 5’ 5’ 5’ 5’ Ye D E E F Xe 5’ F2= 500 lb G G Xg Yg 5’ F1 = 500 lb C C Xc
DALAM KEADAAN SETIMBANG ∑X = 0 +Xf- Xe = 0 Xf – 1500 = 0 Xf = 1500 lb MENENTUKAN GAYA DI DEF DALAM KEADAAN SETIMBANG ∑X = 0 +Xf- Xe = 0 Xf – 1500 = 0 Xf = 1500 lb ∑Y = 0 -Ye + Yf + 500 = 0 Yf = Ye – 500 1) ∑Mf = 0 -F2.10 + Ye.5 = 0 5.Ye = 500.10 Ye = 5000/5 Ye = 1000 LB 2) SUMBITUSIKAN 2 PADA 1 Yf = 500 lb BESARNYA Yg DIHITUNG DENGAN Ya – Ye – Yg = 0 Yg = 1500 – 100 Yg = 500 lb Ya Rb A B Xa 5’ 5’ 5’ 5’ D E F Yf Ye 5’ E F F2= 500 lb D G 1500 lb 500 lb 5’ F1 = 500 lb C
MENETUKAN GAYA Yg ∑Y = 0 Ya – Ye – Yg = 0 Yg = Ya – Ye Yg = 500 lb y Ya Ya Rb A B A Xa Xa 5’ 5’ 5’ 5’ D E E F Xe Ye 5’ F2= 500 lb G G Xg Yg 5’ F1 = 500 lb C C Xc
Ya Rb Xa A B 500 lb 5’ 5’ 5’ B D 500 lb E F 5’ 1500 lb F2= 500 lb E G C
β ∑ ∑ β √