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Diterbitkan olehDhie Adji Telah diubah "10 tahun yang lalu
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MODUL 11 γ (6) γ (6) = 5 γ (5) = 5 ! γ (6) 2.!.γ (2,5) γ (6) = Jawab :
Integral Dalam Fungsi Gamma dan Fungsi Beta 11.1 Fungsi Gamma Suatu Fungsi Gamma didefinisikan oleh : γ (n) = γ (n + 1) = n γ (n) = n ! Dalam suatu integral Fungsi Gamma didefinisikan dengan : n γ (n) = ∫ x n – 1 e – x dx Misal : γ (6) 2γ (3) 1. = Jawab : γ (6) = 5 γ (5) = 5 ! γ (3) = 2 γ (2) = 2 ! γ (6) 2γ (3) maka : = = 5 ! / 2. 2 ! = 30 γ (3).γ ( 2,5) γ (9 / 2) 2.!.γ (2,5) (4,5).(3,5).(2,5).γ (2,5) 2. = = 16/315. γ (6) 2γ (3) 2.1. =
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γ (6) 2.!.γ (2,5) γ (6) γ (6) = 5 γ (5) = 5 ! γ (6) 2.!.γ (2,5) γ (6)
2γ (3) maka : = = 5 ! / 2. 2 ! = 30 γ (3).γ ( 2,5) γ (9 / 2) 2.!.γ (2,5) (4,5).(3,5).(2,5).γ (2,5) 5. = = 16/315. γ (6) 2γ (3) 5.1. = Jawab : γ (6) = 5 γ (5) = 5 ! γ (3) = 2 γ (2) = 2 ! γ (6) 2γ (3) maka : = = 5 ! / 2. 2 ! = 30 γ (3).γ ( 2,5) γ (9 / 2) 2.!.γ (2,5) (4,5).(3,5).(2,5).γ (2,5) 6. = = 16/315. γ (6) 2γ (3) 6.1. = Jawab : γ (6) = 5 γ (5) = 5 ! γ (3) = 2 γ (2) = 2 ! γ (6) 2γ (3) maka : = = 5 ! / 2. 2 ! = 30
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2.!.γ (2,5) γ (6) γ (6) = 5 γ (5) = 5 ! γ (6) 2.!.γ (2,5) γ (6)
γ (3).γ ( 2,5) γ (9 / 2) 2.!.γ (2,5) (4,5).(3,5).(2,5).γ (2,5) 9. = = 16/315. γ (6) 2γ (3) 9.1. = Jawab : γ (6) = 5 γ (5) = 5 ! γ (3) = 2 γ (2) = 2 ! γ (6) 2γ (3) maka : = = 5 ! / 2. 2 ! = 30 γ (3).γ ( 2,5) γ (9 / 2) 2.!.γ (2,5) (4,5).(3,5).(2,5).γ (2,5) 10. = = 16/315. γ (6) 2γ (3) 10.1. = Jawab : γ (6) = 5 γ (5) = 5 ! γ (3) = 2 γ (2) = 2 ! γ (6) 2γ (3) maka : = = 5 ! / 2. 2 ! = 30 γ (3).γ ( 2,5) γ (9 / 2) 2.!.γ (2,5) (4,5).(3,5).(2,5).γ (2,5) 11. = = 16/315.
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