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Diterbitkan olehYuda Rizq Telah diubah "9 tahun yang lalu
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PONDASI DANGKAL MEKANIKA TANAH II YULVI ZAIKA Powerpoint Templates
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SYARAT- SYARAT PEMILIHAN PONDASI
KEDALAMAN TANAH KERAS BEBAN YANG DITAHAN BIAYA YANG TERSEDIA PENGARUH-PENGARUH LAIN
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PONDASI TELAPAK Lapisan Tanah Keras
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Combined footing If P2/P1 < 1/2, use strap combined footing
property line 2 footings close to each other P1 close to property line and P2 > P1 property line P1 P2 If 1/2 < P2/P1 < 1 use trapezoidal footing property line P1 P2
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BENTUK PONDASI TELAPAK
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PONDASI TELAPAK MENERUS/ LAJUR
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PONDASI RAKIT
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PONDASI RAKIT
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PONDASI RAKIT
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SYARAT PONDASI DANGKAL
Kedalaman tanah pondasi kurang atau sama dengan lebarnya atau kedalaman (Terzaghi, 1943). Teori lain, kedalaman pondasi dangkal 3-4 kali lebar pondasi. Pondasi setempat harus memenuhi syarat-syarat: Stabilitas, aman terhadap keruntuhan geser deformasi harus lebih kecil dari yang diizinkan. Lapisan Tanah Keras Df B
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METODA PELAKSANAAN
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KERUNTUHAN PADA PONDASI DANGKAL PADA TANAH PASIR PADAT DAN LEMPUNG KAKU
B
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MODEL KERUNTUHAN GESER
Beban/luas Penurunan qu qu1 Permukaan runtuh (a) (b) (c) keruntuhan umum geser pasir padat Dr>67% lempung kaku NSPT >12 Koruntuhan lokal pasir atau pasir kelempungan kurang padat (medium) 30%<Dr<67% Keruntuhan penetrasi Pasir lepas Dr< 30%
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MODEL KERUNTUHAN BERDASARKAN RELATIF DENSITY
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Terzaghi Assumptions Df ≤ B c = 0 above ( F.L ).
1. Soil under footing is homogeneous and isotropic 2. Soil surface is horizontally 3. The base of footing is rough, to prevent the shear displacement. 4 The foot is shallow foundation, i.e. the depth of foundation is less than the width of foot… Df ≤ B 3. Shear strength above the level of the base of footing is negligible. c = 0 above ( F.L ). 4. Consider only the surcharge which produced as uniform pressure q = DF at foundation level. 5. The load on foundation is vertical and uniform. 6. The foot is long strip footing (pondasi lajur, B/L 0). =
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Shear failure happened on many stages
I) Stage I: The soil in the elastic case and behave as the part of foundation it still that, and by increasing the load performed the region I which called active zone. II) Stage II: At this stage the foundation load effect on the active zone and neighboring soil so perform the region which called arc of logarithmic spiral zone. III) Stage III: By increasing the load performed the third part curve in which part the soil became in the passive case it make to resist the failure.
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PROSES TERJADINYA KERUNTUHAN
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Three components produced to resist the failure of soil.
I) (Pp)γ = Component produced by the weight of shear zone II, III. II)(Pp)c = Component produced by the cohesive stress. III) (Pp)q = Component produced by the surcharge q. Pp = (Pp)γ + (Pp)c + (Pp)q
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DASAR PENURUNAN RUMUS TERZAGHI
Kesetimbangan Gaya qu(2b)= -W+ 2Pp+f sin f W=(1/2)2bg btan a=b2gtanf f=c DC= c. b/cosf Pp=(1/2)g (b tan f)2 Kg + c (b tan f)Kc +q(b tan f) Kq qu =c{tan f (Kc +1)} +q(tan f Kq) + g B/2{(1/2) tan f(Kg. tan f-1)} qu A B J Pp W f B=2b Zona aktif Zona pasif Zona geser radial
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PERSAMAAN DAYA DUKUNG TERZAGHI UNTUK PONDASI LAJUR/ MENERUS
Nq = Nc = = e
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TEORI DAYA DUKUNG TERZAGHI (1943)
Pondasi lajur Pondasi bujursangkar Pondasi lingkaran Untuk keruntuhan geser lokal: c’ = 2/3 c dan f’ = 2/3f qu q=gDf B Df 45-f/2 a A C D E F H G J I
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GRAFIK FAKTOR DAYA DUKUNG
Local shear failure General shear failure
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PERBANDINGAN BIDANG RUNTUH
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RUMUS UMUM DAYA DUKUNG PONDASI MEYERHOF (1963)
Fcs , Fqs , Fs = faktor bentuk Fcd , Fqd , Fd = faktor kedalaman Fci , Fqi , Fi = faktor inklinasi
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FAKTOR PENGARUH MEYERHOF
F. BENTUK F. KEDALAMAN F. INKLINASI b Q T R
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DISTRIBUSI TEGANGAN TANAH AKIBAT TEG. VERTIKAL DAN MOMEN
P M
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Tegangan kontak akibat beban vertikal dan momen
P M B R e e < B/6 qmax qmin e > B/6 qmax qmin e = B/6 qmax qmin
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P e e = B/6 qmax qmin e < B/6 qmax qmin e > B/6 qmax qmin
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Pondasi Lajur e B B-2e
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Stabilitas Daya Dukung
Tegangan kontak : tegangan akibat beban Menentukan eksentrisitas DPT C
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