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Diterbitkan olehAlfian Azizi Telah diubah "9 tahun yang lalu
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OLEH : KIBOGOWONTO
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R 1 R 2 R 3 R 4
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R 1 R 2 R 3 Hitung yang pararel terlebih dulu sehingga didapat R TP R TP R 3 R TOTAL RANGKAIAN (RT) = R TP + R 3 1 2 A
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R 1 = 4ΩR 2 = 4Ω R 3 = 6Ω R TP R3R3 R TOTAL RANGKAIAN (RT) = 8 Ω 1 2 A 1/R TP = 1/R 1 + 1/R 2 1/R TP = 1/4 + 1/4 1/R TP = 2/4 2 R TP = 4 R TP = 4 / 2 = 2Ω 2 6 3
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R 1 R 2 R 3 Hitung R TP R TP R 3 R TOTAL RANGKAIAN (RT) = R TP + R TS 2 B R 4 Hitung R TS R TP R TS 1
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R 1 = 4ΩR 2 = 4Ω R 3 = 6Ω 2 12 R TOTAL RANGKAIAN (RT) = 2 + 12 = 16 Ω 1 2 B 1/R TP = 1/R 1 + 1/R 2 1/R TP = 1/4 + 1/4 1/R TP = 2/4 2 R TP = 4 R TP = 4 / 2 = 2Ω R 4 = 6Ω R TS = R 1 + R 2 R TS = 6 + 6 R TS = 12Ω R TP R TS 2
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R 2 R 3 R 1 Hitung R TP R TP R 1 R TOTAL RANGKAIAN (RT) = R 1 + R TP + R 4 1 2 C R 4
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R 2 = 4ΩR 3 = 8Ω R 4 = 6Ω R TP R4R4 R TOTAL RANGKAIAN (RT) = 8 + 2,6 + 6 =16,6 Ω 1 2 C 1/R TP = 1/R 2 + 1/R 3 1/R TP = 1/4 + 1/8 1/R TP = 3/8 3 R TP = 8 R TP = 8 / 3 = 2,6 Ω 2,6 6 3 R 1 = 8ΩR1R1 8
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R 1 R 2 R 3 R TP1 R TS R TOTAL RANGKAIAN (RT) = R TP1 + R TS + R TP2 2 D R 4 Hitung R TP1 R TP2 R 5 R 6 Hitung R TS Hitung R TP12 1
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R 4 = 6Ω R 1 = 4ΩR 2 = 4Ω R 3 = 6Ω R TOTAL RANGKAIAN (RT) = 2 + 12 + 2,6 = 16,6 Ω 1 D 1/R TP = 1/R 1 + 1/R 2 1/R TP = 1/4 + 1/4 1/R TP = 2/4 2 R TP = 4 R TP = 4 / 2 = 2Ω R TS = R 1 + R 2 R TS = 6 + 6 R TS = 12Ω 2 R 5 = 4ΩR 6 = 8Ω 1/R TP2 = 1/R 2 + 1/R 3 1/R TP2 = 1/4 + 1/8 1/R TP2 = 3/8 3 R TP2 = 8 R TP2 = 8 / 3 = 2,6 Ω 34 R TP1 R TS R TP2 5 2 122,6
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R 1 = 40 ΩR 2 = 20Ω R 3 = 16Ω 1
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R 2 = 30 ΩR 3 = 20Ω R 4 = 16Ω 2 R 1 = 30Ω R 5 = 50Ω
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R 3 = 30 ΩR 4 = 10Ω R 5 = 16Ω 3 R 2 = 30Ω R 6 = 50Ω R 1 = 30Ω
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R 3 = 30 ΩR 4 = 10Ω R 6 = 20Ω 4 R 2 = 60Ω R 7 = 50Ω R 1 = 30Ω R 5 = 10Ω
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R 1 = 30 ΩR 2 = 40Ω R 4 = 60Ω 4 R 5 = 30Ω R 3 = 10ΩR 6 = 40 ΩR 7 = 20ΩR 8 = 20Ω
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