Statistika Deskriptif Tugas Notasi Sigma
Nama : rahma aprilia handayani KELAS : 11.2A.05 NIM : 11141704
Notasi Sigma Diketahui : X1 = 3 X2 = 4 X3 = 6 , Y1 = 2 Y2 = 3 Y3 = 1 Variabel X : 2 4. ∑ Xi 2 - 3 = (X12 + X22) - 3 = (32 + 42)-3 = (9 + 16) – 3 = 25-3 = 22 i=1 5. ∑ (Xi 2 – 3) = (32 - 3) + (42 - 3) = (9-3) + (16-3) = 6 + 13 = 19 3 6. ∑ 7 = 3.7 = 21
Notasi Sigma Diketahui : X1 = 3 X2 = 4 X3 = 6 , Y1 = 2 Y2 = 3 Y3 = 1 Variabel X : 9. ∑ Xi2 - 4 = (x12 + x22)-4 = (32 + 42)-4 = (9 +16)-4 =21 2 i=1 7. ∑ 3Xi 2 = 3Xi2 + 3Xi2 = 3.32 + 3.42 = 81 + 24 = 105 10. ∑ 5Xi2 + 2xi = 5x12 + 2x1 + 5x22 + 2x2 i=1 i=1 = 5.32 + 2.3 + 5.42 + 2.4 8. ∑ (Xi – 3) = (x1 – 3)2 + (x2 – 3)2 = (3- 3)2 + (4-3)2 = 325 + 6 + 400 + 8 i=1 = 02 + 12 = 739
Notasi Sigma Diketahui : X1 = 3 X2 = 4 X3 = 6 , Y1 = 2 Y2 = 3 Y3 = 1 Variabel Y : 3 1. ∑ Yi = Y1 + Y2 + Y3 = 2 + 3 + 1 = 6 i=1 2 2. ∑ 4yi = 4y1 + 4y2 + 4y3 = 4.2 + 4.3 + 4.1 = 8 + 12 + 4 = 24 3. ∑ yi 2 = y1 2 + y2 2 = 22 + 32 = 4 + 9 = 13
Notasi Sigma Diketahui : X1 = 3 X2 = 4 X3 = 6 , Y1 = 2 Y2 = 3 Y3 = 1 Variabel Y : 2 4. ∑ yi 2 - 3 = (y12 + y22) - 3 = (22 + 32)-3 = (4 + 9) – 3 = 13-3 = 10 i=1 5. ∑ (yi 2 – 3) = (y1 2 – 3) + (y2 2 – 3) = (22 - 3) + (32 - 3) = (4-3) + (9-3) = 1 + 6 = 7 3 6. ∑ 7 = 3.7 = 21
Notasi Sigma Diketahui : X1 = 3 X2 = 4 X3 = 6 , Y1 = 2 Y2 = 3 Y3 = 1 Variabel Y : 2 7. ∑ 3yi 2 = 3y12 + 3y22 = 3.22 + 3.32 = 12 + 81 = 93 i=1 8. ∑ (yi – 3) = (y1 – 3)2 + (y2 – 3)2 = (2-3)2 + (3-3)2 = 12 + 02 i=1 9. ∑ yi2 - 4 = (y12 + y22)-4 = (22 + 32)-4 = (4 + 9)-4 = 9
Notasi Sigma Diketahui : X1 = 3 X2 = 4 X3 = 6 , Y1 = 2 Y2 = 3 Y3 = 1 Variabel Y : 2 10. ∑ 5yi2 + 2yi = 5y12 + 2y1 + 5y22 + 2y2 i=1 = 5.22 + 2.2 + 5.32 + 2.3 = 100 + 4 + 225 + 6 = 335