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Medan Listrik (Electric fields) Hukum Coulomb  bagaimana muatan listrik berinteraksi dengan muatan listrik yang lain. Tetapi bagaimana muatan listrik.

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Presentasi berjudul: "Medan Listrik (Electric fields) Hukum Coulomb  bagaimana muatan listrik berinteraksi dengan muatan listrik yang lain. Tetapi bagaimana muatan listrik."— Transcript presentasi:

1 Medan Listrik (Electric fields) Hukum Coulomb  bagaimana muatan listrik berinteraksi dengan muatan listrik yang lain. Tetapi bagaimana muatan listrik tersebut ‘tahu’ ada kehadiran muatan listrik lain dan juga bagaimana mampu mendeteksi muatan tersebut negatif atau positip? Maka muncul konsep medan listrik

2 Secara ilustratif Satuan medan listrik (N/C) Arah gaya listrik mendefinisikan juga arah medan listrik

3 Garis-garis gaya Listrik (Electric field lines): Michael Faraday (abad 19) : memperkenalkan ide medan listrik dan dipikirkan sebagai ruang di sekitar benda bermuatan listrik dipenuhi oleh garis- garis gaya Garis-garis gaya sebagai cara memvisualisasikan adanya medan listrik Arah garis-garis gaya menunjukkan arah gaya listrik yang bekerja pada tes muatan positip Kerapatan garis gaya sebanding dengan besarnya medan listrik Kekuatan medan terkait dengan jumlah garis-garis yang melintasi satuan luas yang tegak lurus medan

4 Karena gaya listrik adalah Kekuatan (besarnya) medan listrik:

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7 Two positive point charges, q 1 =+16 μ C and q 2 =+4.0 μ C, are separated in a vacuum by a distance of 3.0 m, as Figure illustrates. Find the spot on the line between the charges where the net electric field is zero. Examples:

8 SUPERPOSISI MEDAN LISTRIK

9 Example 5. Vector properties of Electric Fields Two point charges are lying on the y axis in Figure a: q 1 =–4.00 μ C and q 2 =+4.00 μ C. They are equidistant from the point P, which lies on the x axis. (a) What is the net electric field at P?

10 MEDAN LISTRIK dari distribusi muatan listrik

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12 Electric dipole 電偶極 In nature, many molecules carry no net charge, but there are still finite electric fields around the molecules. it is because the charge are not uniformly distributed, the simplest form of charge distribution is a electric dipole, as shown in the figure. one can calculate the electric field along the z-axis as follows:

13 Rewrite the electric field in the following form: Because we are usually interested in the case where z>>d, therefore we can use an approximation to simplify E: Throw away higher order terms of d/z, Or with p=qd (electric dipole moment),

14 Note the dipole electric field reduces as 1/r 3, instead of 1/r of a single charge. although we only calculate the fields along z-axis, it turns out that this also applies to all direction. p is the basic property of an electric dipole, but not q or d. Only the product qd is important. E E p

15 Electric field due to a line charge we now consider charges uniformly distributed on a ring, rather than just a few charges. again we use the superposition principle of electric fields, just as what we have done on electric dipoles. assume the ring has a linear charge density λ. then for a small line element ds, the charge is So it produces a field at point P of:

16 Or rewrite as Here we only consider the field along z-axis, dEcosθ, because any fields perpendicular to z direction will be cancelled out at the end. since Sum over all fields produced by other elements on the ring:

17 An infinite long line charge For an infinite line,

18 A point charge in an electric field By the definition of electric field, a point charge will experience a force equal to: The motion of a point charge can now be described by Newton’s law. Robert A. Millikan, in 1909, made use of this equation to discover that charge is quantized and he was even able to find the value of fundamental charge e=1.6x C. The electric field between the plates are adjusted so that the oil drop doesn’t move: He found that q=ne, always a multiple of a fundamental charge e.

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20 Dipole in an electric field The response of an electric dipole in an electric field is different from a charge in an electric field. Since a dipole has no net charge, so the net force acting on it must be zero. however, each charge in the dipole does experience forces from the field. the forces are equal in magnitude but opposite in direction, and so there is net torque Or in vector form p is the dipole moment 偶極 矩

21 Therefore, a dipole in an uniform electric field experiences a torque that is proportional to the dipole moment, and does not depends on any detail of the dipole. Potential energy Under the effect of the field, the dipole will now oscillates back and forth, just like a pendulum under the effect of gravitation field. The motion of the dipole of cause requires energy. The work done on dipole by the torque is Similar to gravitation potential, we can define a electric potential energy of the dipole in an electric field :

22 In the vector form, the potential energy is simply a dot product of the dipole moment and the field. The potential energy is the lowest when the angle = 0 (equilibrium position) and has the largest values when the angle = 180°. If there is energy loss to the surroundings, the oscillation will die out gradually unless energy is pumped in continuously from the field (an oscillating field). This is essentially the principle of a microwave oven. Water molecule has large dipole moment of 6.2x Cm. the dipoles vibrate in response to the field and generate thermal energy in the surrounding medium materials such as paper and glass, which has no dipoles, do not become warm

23 The large dipole moment of water molecule attracts Na and Cl ions and breaks the ionic bond between these ions. Therefore, salt dissolves easily in water. Note: A dipole in an uniform field experiences no net force, but it does in a non-uniform field. F + >F - Induced dipole Charges in the comb produce a non-uniform field

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25 (a)τ=0 (b)τ=pE (c)τ=0 the field produced by the rings is

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27 (a) (b)

28 電四極


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