MATERI 6 VLSM
Contoh kasus Ip yang digunakan : 172.168.192.0 /24
Penyelesaianya Rumusan 128 64 32 16 8 4 2 1 Awal (172.168.192.0/24) 58 komputer (A) Rumusan 128 64 32 16 8 4 2 1 Awal (172.168.192.0/24) 00000000 172.168.192.0/26 NA 00111111 BA Patokan length 128 = /25 64 = /26 32 = / 27
28 komputer(D) Rumusan 128 64 32 16 8 4 2 1 Awal (172.168.192.0/24) 128 64 32 16 8 4 2 1 Awal (172.168.192.0/24) 00000000 172.168.192.0/27 NA 00011111 BA
10 komputer (B) Rumusan 128 64 32 16 8 4 2 1 Awal (172.168.192.0/24) 128 64 32 16 8 4 2 1 Awal (172.168.192.0/24) 00000000 172.168.192.0/28 NA 00001111 BA
10 komputer Rumusan 128 64 32 16 8 4 2 1 Awal (172.168.192.0/24) 128 64 32 16 8 4 2 1 Awal (172.168.192.0/24) 00000000 172.168.192.16/28 NA 00011111 BA
Kesimpulan Ip tak terpakai : Rumus ip tak terpakai : jumlah bit – banyaknya komputer A (58 komputer) : 64 – 58 = 6 B (10 komputer) : 14 (16 – 2(BA & NA)) – 10 = 4 C (10 komputer) : 14 (16 – 2(BA & NA)) – 10 = 4 D (28 komputer) : 32 – 28 = 4
Tugas