PEMBAHASAN TRYOUT MATEMATIKA

Perbandingan Berbalik Nilai = (80 x 45) : 60 = 60 (C) NOMOR 1 Perbandingan Berbalik Nilai = (80 x 45) : 60 = 60 (C) 2 15 4

Bilangan Berpangkat = 8(24)-3/4 x 9(33)2/3 = 8 x 1/8 x 9 x 9 = 81 (D) NOMOR 2 Bilangan Berpangkat = 8(24)-3/4 x 9(33)2/3 = 8 x 1/8 x 9 x 9 = 81 (D)

NOMOR 3 Pecahan Bentuk Akar D

Logaritma = 3log (18 x 36): 24 = 3log 27 = 3log 33 = 3 (B) NOMOR 4 Logaritma = 3log (18 x 36): 24 = 3log 27 = 3log 33 = 3 (B) 9 3 2

NOMOR 5 Persamaan Linear Satu Variabel 4(3x + 6) – 3(2x – 4) = 12 . 5 12x + 24 – 6x + 12 = 60 6x + 36 = 60 6x = 24 x = 4 (E)

2(x – 6) – 3 ≥ 6 + 3(2x + 1) 2x – 12 – 3 ≥ 6 + 6x + 3 -4x ≥ 24 NOMOR 6 Pertidaksamaan Linear Satu Variabel 2(x – 6) – 3 ≥ 6 + 3(2x + 1) 2x – 12 – 3 ≥ 6 + 6x + 3 -4x ≥ 24 x ≤ -6 (C)

NOMOR 7 x2 + 4x – 12 = 0  PKL PKB  (x + 1)2 + 4(x + 1) - 12 = 0 Persamaan Kuadrat Baru x2 + 4x – 12 = 0  PKL PKB  (x + 1)2 + 4(x + 1) - 12 = 0 (x2 + 2x + 1) + (4x + 4) – 12 = 0 x2 + 6x – 7 = 0 (A)

NOMOR 8 2x2 + 9x + 4 ≤ 0 (2x + 1)(x + 4) ≤ 0 x = -1/2 ˅ x = -4 Pertidaksamaan Kuadrat 2x2 + 9x + 4 ≤ 0 (2x + 1)(x + 4) ≤ 0 x = -1/2 ˅ x = -4 Karena tanda soal ≤, maka x nya di tengah-tengah. (C)

NOMOR 9 b = 1.500 3b = 4.500 (D) 2b + 4p = 6 |x1 |2b + 4p = 6 Persamaan Linear Dua Variabel 2b + 4p = 6 |x1 |2b + 4p = 6 5b + 2p = 9 |x2 | 10b + 4p = 18 -8b = -12.000 b = 1.500 3b = 4.500 (D)

NOMOR 10  a = -1 2a – c = 7 -2 – c = 7  c = -9 a + b = c -1 + b = -9 Kesamaan Matriks  a = -1 2a – c = 7 -2 – c = 7  c = -9 a + b = c -1 + b = -9 b = -8 (E)

MT = Matriks M Transpose (Baris jadi kolom) NOMOR 11 Operasi Matriks (Perkalian Matriks) Baris x Kolom MT = Matriks M Transpose (Baris jadi kolom) ~ (-3 x 2) + (4 x 1) = -2 (A)

NOMOR 12 Det M = (-3 x -3) – (5 x 2) = 9 – 10 = -1 M-1 = -1 = (E) Invers Matriks Det M = (-3 x -3) – (5 x 2) = 9 – 10 = -1 M-1 = -1 = (E)

NOMOR 13 Operasi Matriks (Pengurangan Matriks) 2A = 2 = 3B = 3 = Jadi  Transpose

Determinan Matriks Ordo 3 x 3 BONUS NOMOR 14 Determinan Matriks Ordo 3 x 3 BONUS

NOMOR 15 Luas Tanah  300x + 200y ≤ 21600 3x + 2y ≤ 216 Model Matematika Luas Tanah  300x + 200y ≤ 21600 3x + 2y ≤ 216 Banyak  x + y ≤ 96  x ≥ 0, y ≥ 0 (Otomatis) (C)

NOMOR 16 x ≥ 0, y ≥ 0 Program Linear Ttk sb.y dikalikan x. Ttk sb.x dikalikan y = ttk sb.x dikalikan ttk sb. Y  3x + 6y ≤ 18  x + 2y ≤ 6 4x + 2y ≥ 8  2x + y ≥ 4 x ≥ 0, y ≥ 0 (B)

C NOMOR 17 Jadi titik yang membatasi Hp (0,4) 6.0 + 4.4 = 0 + 16 = 16 Nilai Optimum (Maksimum dan Minimum) x + 2y = 8 3x + 2y = 12 -2x = -4 x = 2 y = 3 Jadi titik yang membatasi Hp (0,4) 6.0 + 4.4 = 0 + 16 = 16 (4,0) 6.4 + 4.0 = 24 + 0 = 24 (2,3)  6.2 + 4.3 = 12 + 12 = 24 C

NOMOR 18 Bangun Datar (Keliling) K lingkaran = 2r K 3/4kecil = ¾ . 2 . 22/7 . 7 = 33 cm K 1/2besar = ½ . 2 . 22/7 . 10,5 K bangun = 14 + 7 + 33 + 33 = 87 cm (A) 1,5

NOMOR 19 Bangun Datar (Luas) Luas  = ¼ d2 = ¼ . 22/7 . 3,5. 3,5 = 9,625 Luas  = p x l = 1 x 0,25 = 0,25 Luas Rumput Taman = 9,625 – 0,25 = 9,375 ( C)

NOMOR 20 Luas persegi = s x s = 28 x 28 = 784 Luas ¾  = ¾ x r2 Bangun Datar (Luas) Luas persegi = s x s = 28 x 28 = 784 Luas ¾  = ¾ x r2 = ¾ x 22/7 x 14 x 14 = 462 Luas yang diarsir = 784 – 462 = 322 (D) 11 2

NOMOR 21 Keliling = prinsip penjumlahan Sisi miring = 10 (Phytagoras) Bangun Datar (Keliling) Keliling = prinsip penjumlahan Sisi miring = 10 (Phytagoras) Keliling = 16 + 12 + 16 + 20 = 64 (A)

NOMOR 22 5x – 3y = 15 – 6 = 9 (C) 5x + 3y = 21 |x2 |10x + 6y = 42 Persamaan Linear Dua Variabel 5x + 3y = 21 |x2 |10x + 6y = 42 4x + 2y = 16 |x3 |12x + 6y = 48 -2x = -6 x = 3 y = 2 5x – 3y = 15 – 6 = 9 (C)

Cukup Jelas !!! (Metode Coba-Coba) NOMOR 23 Barisan Bilangan(Rumus suku ke-n) Cukup Jelas !!! (Metode Coba-Coba) (E)

NOMOR 24 Barisan Aritmetika U2 a + b = 7.....................(1) U4 + U6 (a + 3b) + (a + 5b) = 50  2a + 8b = 50........(2) 2a + 2b = 14 2a + 8b = 50 -6b = -36 b = 6 a = 1 U11 = a + 10b = 1 + 60 = 61 (B)

NOMOR 25 Gaji pokok = 5 x 12 x 100.000 = 6.000.000 Kenaikan Gaji Jumlah Barisan Aritmetika Gaji pokok = 5 x 12 x 100.000 = 6.000.000 Kenaikan Gaji = 59 x 5.000 = 295.000 Jumlah gaji 5 tahun = 6.295.000 (B)

NOMOR 26  375 x 25 = 9375 (E) U6  U4 x r2 U1 = a = 3 U4 ar3 = 375 Barisan Geometri U1 = a = 3 U4 ar3 = 375 3r3 = 375  r3 = 125  r = 5 U6  U4 x r2  375 x 25 = 9375 (E)

NOMOR 27 Deretnya = 5 + 2 + 4/5 = 7 4/5 (C) U1 = a = 5 U3 ar2 = 4/5 Deret Geometri U1 = a = 5 U3 ar2 = 4/5 5r2 = 4/5  r2 = 4/25  r = 2/5 U2 = 5 x 2/5 = 2 Deretnya = 5 + 2 + 4/5 = 7 4/5 (C)

S~ = a/1 – r NOMOR 28 (B) S~ = 25 / (1 – 1/5) S~ = 25 / 4/5 Deret Geometri Tak Hingga S~ = a/1 – r S~ = 25 / (1 – 1/5) S~ = 25 / 4/5 S~ = 25 x 5/4 = 125/4 = 31 ¼ (B)

NOMOR 29 Statistika = 60 (E) Pendidikan SMK = 40/100 x 150 Diagram Lingkaran Dalam Derajat = 360o (Siku-siku = 90o) Dalam Persen = 100% (Siku-siku = 25%) Pendidikan SMK = 40/100 x 150 = 60 (E)

NOMOR 30 (x – 6)(x + 4) x = 6 atau x = -4 (A) Memfaktorkan (Kecepatan) Akar-Akar Persamaan Kuadrat Memfaktorkan (Kecepatan) Rumus Kecap (Ketelitian) Coba-Coba (Keikhlasan) x2 – 2x -24 = 0 (x – 6)(x + 4) x = 6 atau x = -4 (A)

(D) NOMOR 31 KV = (SD /x ) . 100% 30% = (SD / 50) . 100% SD = 15 Koefisien Variasi (KV) KV = (SD /x ) . 100% 30% = (SD / 50) . 100% SD = 15 (D)

x = 48/8 = 6 SR = (2+1+1+2+2+2+3+3) : 8 NOMOR 32 SR = 2,00 (A) Simpangan Rata-Rata x = 48/8 = 6 SR = (2+1+1+2+2+2+3+3) : 8 SR = 2,00 (A)

NOMOR 33 Standar Deviasi BONUS!!!!

NOMOR 34 (E) SK = (Q3 – Q1) : 2 Data Diurutkan! Q3 = 65, Q1 = 45 Jangkauan Semi Interkuartil SK = (Q3 – Q1) : 2 Data Diurutkan! Q3 = 65, Q1 = 45 Jadi SK = 10 (E)

Angka Baku Z = (x -x) : SD 2 = (x – 70) : 4 8 = x – 70 x = 78 NOMOR 35 Angka Baku Z = (x -x) : SD 2 = (x – 70) : 4 8 = x – 70 x = 78